Jawab:
1.) 5 = 2 kali muncul
6 = 1 kali muncul
7 = 3 kali muncul
8 = 2 kali muncul
9 = 3 kali muncul
10 = 1 kali muncul
[Banyak data (n) = 12]
Mean (rata-rata) = jumlah nilai data / banyak data
[tex]Mean = \frac{(5X2)+(6X1) + (7X3) + (8X2) + (9X3) + (10X1)}{12} \\Mean = \frac{10+6 + 21 + 16 + 27+10}{12} \\Mean = \frac{90}{12} \\Mean = 7,5[/tex]
Median data ke = [tex]\frac{n+1}{2} = \frac{12+1}{2} = \frac{13}{2}[/tex]
Median data ke = 6,5
Median = [tex]\frac{7+8}{2} = \frac{15}{2} = 7,5[/tex]
Modus (yang paling banyak muncul) = 7 dan 9 (3 kali muncul)
Jangkauan data (selisih dari nilai data terbesar dan terkecil) = 10 - 5 = 5
5, 5, 6, 7, 7, 7, 8, 8, 9, 9, 9, 10
↓ ↓ ↓
Q1= [tex]\frac{6+7}{2}[/tex]=6,5 ↓ Q3 = 9
Q2 = 7,5
Jangkauan antarquartil (H) = Q3 - Q1 = 9 - 6,5 = 2,5
Simpangan kuartil = [tex]\frac{1}{2} (H) = \frac{1}{2} (2,5) = 1,25[/tex]
2.) 60 = 2 kali muncul
70 = 3 kali muncul
80 = 4 kali muncul
90 = 2 kali muncul
100 = 2 kali muncul
(Banyak data = 13)
[tex]Mean = \frac{(60X2)+(70X3)+(80X4)+(90X2)+(100X2)}{13}\\Mean = \frac{120+210+320+180+200}{13}\\Mean = \frac{120+210+320+180+200}{13}\\Mean = \frac{1030}{13}[/tex]
[tex]Mean = 79\frac{3}{13}[/tex] atau 79,23
Median data ke = [tex]\frac{n+1}{2} = \frac{13+1}{2} = \frac{14}{2}[/tex]
Median data ke = 7
Median = 80
Modus = 100 (2 kali muncul)
Jangkauan Data = 100 - 60 = 40
60, 60, 70, 70, 70, 80, 80, 80, 80, 90, 90, 100, 100
↓ ↓ ↓
Q1 = 70 ↓ Q3 = 90
Q2 (Median) = 80
Jangkauan antarquartil (H) = Q3 - Q1 = 90 - 70 = 20
Simpangan kuartil = [tex]\frac{1}{2} (H) = \frac{1}{2} (20) = 10[/tex]
Jawaban:
semoga membantu, bantuin jadiin jawaban terbaik ya kalau bener:)
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